How do you solve the integral of (cosx)^3 times (sinx)^3 dx?

both of the cosine and sine have odd exponents and this case is something I haven't yet encountered, I was able to solve a problem similar to this only that one of the exponents is even. Even when I try to use a bunch of trigonometric identities, it always ends up with both the cosine and sine having an odd exponent, can somebody tell me what to do?